[candiishop]

During experiment, acetic acid reacts with ammonia giving a strong electrolyte completion.

CH3COOH (aq) + NH3 (aq) -----> NH4+ (aq) + CH3COO- (aq)

Why does this reaction proceeds to completion?

Any help would be greatly appreciated

[Borek]

Why does this reaction proceeds to completion?

Depends on what you mean by completion. For 0.1M mixture about 0.4% of both substances remains unreacted.

In what context is this question asked? As for me the only reasonable answer is that both acetic acid and ammonia are (albeit weak) strong enough for the quilibrium of neutralization to be shifted to the right.

[candiishop]

Oh... sorry forgot to mention. 1:1 mixture 0.2M NH3 and 0.2M CH3COOH

[Borek]

Oh... sorry forgot to mention. 1:1 mixture 0.2M NH3 and 0.2M CH3COOH

Doesn't change much. Still about 0.4% left.

[candiishop]

I understand that both are weak acids but how do you get the 0.4% value?

[Borek]

Calculate pH using pH of amphiprotic salt lecture then you may use Henderson-Hasselbalch equation - while its standard application is buffer pH calculation, it works perfectly other side as well - to calculate ratio of conjugated acid and base for known pH.

Or you may go lazy way as I did and do the calculations using BATE