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Topic: kinetics of an enzyme catalysed reaction  (Read 8587 times)

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Offline hardy5086

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kinetics of an enzyme catalysed reaction
« on: June 07, 2016, 07:47:16 PM »
I'm having some trouble with a couple of things and haven't been able to work it out.
so I did a practical and am now trying to do the data analysis of it. the prac was the alpha-chymotrypsin catalyzed hydrolysis of 4-nitrophenyl trimethylacetate.

the lab manual has asked "Using the approximated, simplified expressions for X (equation 2), Y (equation 3)
and B (equation 4), determine kcat, [E]0act and k2/K for each kinetic experiment.
From these values, determine KM and p."

I have calculated kcat, [E]0act and k2/k, but cant work out how to determine km.

equation 2 is simplified to x≈kcat.[E]0act   (if [ S] >>km)
equation 3 is simplified to y≈[E]0act      (if [ S] >>km and k2>>k3)
equation 4 is simplified to B≈k2[ S]/k     (if [ S]>>km and k2>>k3)

where kcat = k2k3/(k2+k3) ≈ k3   (if k2>>k3)
km = k3k/(k2+k3)

Hint: to determine KM, consider how k2/K can be derived from the expressions for
kcat and KM.

I'm getting lost at this bit.
any help would be appreciated.

Edit by Borek: corrected the formatting, [S] is a tag for strikeout which make the post unreadable.
« Last Edit: June 08, 2016, 02:44:37 AM by Borek »

Offline Babcock_Hall

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Re: kinetics of an enzyme catalysed reaction
« Reply #1 on: June 07, 2016, 10:26:49 PM »
Your formatting is unclear and inconsistent.  Some things seem to have been left out entirely.  Can you remedy this?

Offline hardy5086

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Re: kinetics of an enzyme catalysed reaction
« Reply #2 on: June 07, 2016, 11:42:01 PM »
attached is a picture of the page describing the equations they have provided, I'm just unsure how to determine km from this.
I have calculated the values of X, Y, and B so I know, Kcat, [E], and K2[ S ] / K.
I also know the value of [ S ] so have calculated a value of K2/k

Offline hardy5086

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Re: kinetics of an enzyme catalysed reaction
« Reply #3 on: June 07, 2016, 11:53:05 PM »
sorry about the first post, didn't realize when I was trying to put S into brackets for substrate concentration that it would strike through the text instead.

Offline Babcock_Hall

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Re: kinetics of an enzyme catalysed reaction
« Reply #4 on: June 08, 2016, 05:17:32 PM »
It would help if you used subscripts and were consistent about capitalizing K.  If you look a the definitions of KM versus kcat, they contain many common terms. 

Offline hardy5086

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Re: kinetics of an enzyme catalysed reaction
« Reply #5 on: June 08, 2016, 06:45:34 PM »
Sorry again, I typed some and cut and pasted some from the manual so my capitalizing was inconsistent and didn't notice the subscript button above.
I see that they have common terms, but making use of that to solve for Km is where I am getting lost.

Offline Babcock_Hall

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Re: kinetics of an enzyme catalysed reaction
« Reply #6 on: June 08, 2016, 09:08:33 PM »
Try expressing the fraction kcat/KM and see if it helps.

Offline hardy5086

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Re: kinetics of an enzyme catalysed reaction
« Reply #7 on: June 09, 2016, 07:57:07 AM »
Kcat/Km =(K2 K3/(K2+K3 ))/(K3 K/(K2+K3 ))


Ok, from that I can see K2/K
But that is one intimidating equation. I don't even know where to begin trying to rearrange that to solve for Km

Offline Babcock_Hall

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Re: kinetics of an enzyme catalysed reaction
« Reply #8 on: June 09, 2016, 11:17:20 AM »
I may not have properly understood what you are doing.  Are you trying to find a value for KM, or are you trying to express KM in terms of rate constants?

Offline hardy5086

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Re: kinetics of an enzyme catalysed reaction
« Reply #9 on: June 09, 2016, 06:29:38 PM »
Im trying to find a value of Km.

Offline Babcock_Hall

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Re: kinetics of an enzyme catalysed reaction
« Reply #10 on: June 09, 2016, 07:07:31 PM »
attached is a picture of the page describing the equations they have provided, I'm just unsure how to determine km from this.
I have calculated the values of X, Y, and B so I know, Kcat, [E], and K2[ S ] / K.
I also know the value of [ S ] so have calculated a value of K2/k
If you mean "calculated a value of k2/K," then is that what you are looking for?

Offline hardy5086

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Re: kinetics of an enzyme catalysed reaction
« Reply #11 on: June 09, 2016, 08:02:07 PM »
from equation 2, 3 and 4 I have calculated the value of Kcat, [E]oact and knowing [ S] I rearranged equation 4 and calculated a value for K2/K. I need to calculate Km. the "hint" given in the manual is to determine Km, consider how K2/K can be derived from the expression for Kcat and Km. im not sure how to do it.

Offline Babcock_Hall

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Re: kinetics of an enzyme catalysed reaction
« Reply #12 on: June 11, 2016, 05:37:07 PM »
Chemists often use lowercase k's for rate constants and uppercase K's for equilibrium constants and the Michaelis constant. 

You have values for kcat and k2/K, correct?  You previously wrote an equation that can be rearranged to solve for KM  in terms of kcat, K, and k2.  At first pass that seems like all that you need.

Offline Babcock_Hall

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Re: kinetics of an enzyme catalysed reaction
« Reply #13 on: June 11, 2016, 05:43:07 PM »
Kcat/Km =(K2 K3/(K2+K3 ))/(K3 K/(K2+K3 ))


Ok, from that I can see K2/K
But that is one intimidating equation. I don't even know where to begin trying to rearrange that to solve for Km
When you have the same thing in the numerator and denominator, they cancel out.  That should simplify it considerably.

Offline hardy5086

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Re: kinetics of an enzyme catalysed reaction
« Reply #14 on: June 11, 2016, 06:44:51 PM »
I haven't done much maths of this standard and am not exactly sure how to treat a fraction over a fraction when rearranging. you say like terms cancel out so does that mean I can simplify the equation from
Kcat/Km =(K2 K3/(K2+K3 ))/(K3 K/(K2+K3 )) to Kcat/Km = K2 K3/(K3 K) by cancelling out the term (K2+K3) from the top and bottom? and then cancel out the K3 and be left with cat/Km = K2/K ?

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