[lucasloja]

Consider that in the chlorinemethyliodinemethylanthracene molecule, shown below, the speed of rotation around the bond existent between the carbon from iodomethyl and chloromethyl radicals and the aromatic ring carbons are different. While the chloromethyl radical performs a complete turn around that bond, iodomethyl radical travels only 2/3 of a turn. Taking into account this information and the chemical bonding concepts, answer with the sum of the correct alternatives.


01) Being initially the chlorine and iodine atoms in the closest possible position to each other, and both rotations occurring clockwise, a new maximum approach occurs after iodomethyl radical travels an angle of 4π rad.
02) Being initially chlorine and iodine atoms in the farthest position from each other, and rotation occurring in opposite directions, a maximum approach between these atoms occur after iodomethyl radical travels an angle of 720 degrees.
04) The angle formed between the 2 hydrogen atoms and the carbon atom, as in both the chloromethyl and iodomethyl, is less than 109° 28'.
08) Two carbon atoms linked together and both with sp2 hybridization can not undergo rotary motion on the axis of that bond, when they are part of an aromatic structure.
16) The lost of aromaticity of the ring of this molecule will cause no change in the distance between the carbon atoms of the two methyl groups.