Yeah, it must be Iron (III) oxide.
Step 1. Write a balanced equation
Step 2. Work out how many moles of Iron are in 1000g of Iron, let's call that value 'X'.
Step 3. Look at your balanced equation. How many moles of Al react to give one mole of Iron?
In that case, how many moles of Al react to give you the X moles of Iron from step 2? That is how many moles of Al you need.
Step 4. What is the mass of that number of moles of Al?
If you've got it right, your answer should be close to 484g.
I did this calculation using relative atomic masses Fe = 56 and Al = 27, and I got 482g