No, that is impossible. You can tell something is wrong because the charges don't add up - the total charge is zero for structures 1, 2 and 3, +2 for structure 4 and +1 for structure 5.
Going from 3 to 4 you are pushing electrons onto an O- - there is no room for that. 4 should have a double bond between C1 and C2, and a 2- on the carbonyl O (assuming that's possible, which it isn't). 4 to 5, you are taking electrons away from an O+ - is that likely? 5 should have (in addition to the corrections for 4) a double bond between C3 and C4, and a 2+ on the hydroxyl O (not C3). Structures 4 and 5 are impossible (as resonance structures of m-hydroxybenzoic acid), so m-OH does not mesomerically affect the acidity of the acid.
You need to revise the rules for forming resonance structures.