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pH calculation
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light:
the recipe:
0.1 M sodium carbonate buffer, pH 9.6 (Ambros Lab)
8 ml of 0.2M sodium carbonate (Na2CO3) (0.2M = 21.2 g/l)
17 ml of 0.2M sodium bicarbonate (NaHCO3) (0.2M = 16.8 g/l)
25 ml of water
...
i have calculated the pH of this buffer and found that it is not 9.6 but 10.0.
sodium carbonate (Na2CO3): (0.2Mx0.008L)/0.025L=0.064M
sodium bicarbonate (NaHCO3): (0.2Mx0.017L)/0.025L=0.136M
pH=pKa+log[base]/[acid]
pH=10.32+log(0.064/0.136)
pH=10
am i doing it right?
thanks for your input!
AWK:
sodium carbonate (Na2CO3): (0.2Mx0.008L)/0.025L=0.064M
sodium bicarbonate (NaHCO3): (0.2Mx0.017L)/0.025L=0.136M
The final volume is 50 mL (0.05 L) but this not change your result.
Haselbach equation gives quite approximated results, so all is OK at this approximation.
light:
thanks alot for your *delete me*
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