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Topic: Chemistry problem  (Read 15187 times)

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Offline AWK

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Re: Chemistry problem
« Reply #15 on: January 21, 2008, 07:05:14 AM »
Monobasic means a salt with one OH group not neutralized, in the case of eg etylene diamine it means H2NCH2CH2NH2.HCl.
Se also (di)basic copper carbonate CuCO3.Cu(OH)2
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Offline DigiTan

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Re: Chemistry problem
« Reply #16 on: January 21, 2008, 02:47:19 PM »
So even though H2NCH2CH2NH2 doesn't have an oxygen, it could still be a monobasic salt?

Offline AWK

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Re: Chemistry problem
« Reply #17 on: January 22, 2008, 01:10:52 AM »
H2NCH2CH2NH2.HCl (monohydrochloride) is a monobasic salt
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Offline nerd

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Re: Chemistry problem
« Reply #18 on: January 24, 2008, 01:03:44 PM »
1. pOH=14.00-13.07=0.97
2. [OH-]=10^-0.97=0.12M
3. CxV=n=0.12Mx1.00L=0.12mol
4. B/C 100% ionized n(salt)=n(solution)
5. M=m/n=10.00g/0.12mol=85.11g/mol

For my answer the Molar mass makes sense, but please check if it's correct!

Offline Crazy Wood

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Re: Chemistry problem
« Reply #19 on: January 26, 2008, 07:05:45 PM »
1. pOH=14.00-13.07=0.97
2. [OH-]=10^-0.97=0.12M
3. CxV=n=0.12Mx1.00L=0.12mol
4. B/C 100% ionized n(salt)=n(solution)
5. M=m/n=10.00g/0.12mol=85.11g/mol

For my answer the Molar mass makes sense, but please check if it's correct!

I did the same thing but your calculations are kinda wrong i think...

1. pOH = 14.00 - 13.07 = 0.93
2. [OH-] = 10 ^ -0.93 = 0.117 (don't round this... or else you'll get another answer like 83.33 in the end shown in step 4)

3. CxV=n=0.117Mx1.00L=0.117 mol

4. M=m/n=10.00g/0.117mol=85.47g/mol  (if you rounded 0.117 to 0.12 you'll probably get something like..83.33)

Tell me if what I did is right.. i need an answer by Wednesday :(

Offline Kryolith

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Re: Chemistry problem
« Reply #20 on: January 26, 2008, 07:15:27 PM »
Tell me if what I did is right.. i need an answer by Wednesday :(

Your calculation is correct.

Offline Borek

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Re: Chemistry problem
« Reply #21 on: January 26, 2008, 07:16:28 PM »
2. [OH-] = 10 ^ -0.93 = 0.117 (don't round this... or else you'll get another answer like 83.33 in the end shown in step 4)

While it doesn't look so, all numbers (ie yours and nerds) are consistent. You have just two sig figs in the input data, so using more in the final answer doesn't make much sense. This means 85 is a reasonable way of writing down the molar mass and both results (85.11 and 85.47; you have used different numbers of guard digits hence the difference) round down to the same number.
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Offline Kryolith

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Re: Chemistry problem
« Reply #22 on: January 26, 2008, 07:45:43 PM »
Of course you are right Borek. 85.1 g/mol is the correct answer. I just used the value posted by Crazy Wood and did the calculation backwards  ::) (shame on me)

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