[kkennedy91]

A student is adding 1.110g of BaCl₂x6H₂0 to a 1.00L solution containing 0.584g of NaCl.  Calculate the chloride ion concentration in mol/L.  Assume the volume of solution does not change. 

Correct answer is 0.0170 mol/l

Im super lost because we weren't supposed to come up with the chemical formula in order to do this. so I found the mols of hydrated Barium chloride (1.110g/316.24gx1mol)=3.51x10^-3 and also the NaCl which was 1.0x10^-3  that is legitimately where I stopped because I had no idea i think im just really overthinking this because I do truly know how to do chemistry...I just didnt interpret this correctly.  Help

[AWK]

Look at formula of barium chloride. Haw many moles of chloride contains 1 mole of salt? Then add with that of NaCl.

[kkennedy91]

so 2 moles of Chloride per 1 mole of salt?  so 1.110g/70.9 + 0.584/22.99(35.45)?

That seems like it would still be high?

[AWK]

You calculated number of moles for two compounds in 1 liter of solution. This compounds are BaCl₂ (at this moment od calculation water is unimportant) and NaCl. Definition of molar solution is: number of moles in 1 liter of solution. This final calculation can be even done without calculator.
Note - one of your number is wrong.

[bestsciencetutor]

YES YOU WERE SUPPOSED TO FIND THE CHEMICAL FORMULAS OF BaCl2 and NaCl.  You cannot do the problem without them. Who or whatever is tell you that is lying to you.

(1.110g/316.24gx1mol)=3.51x10-3 and also the NaCl which was 1.0x10-3

Always ask yourself what are the units of the final answer and how do those relate to what units you have.  What were the units of your answer?  Always write that down.


Think of atoms and ions as the same thing.  How many atoms of Cl- do you have?

[AWK]

and also the NaCl which was 1.0x10-3

[Borek]

YES YOU WERE SUPPOSED TO FIND THE CHEMICAL FORMULAS OF BaCl2 and NaCl.

Please don't shout.

What is there to find if both formulas are given in the problem?

Irrelevant parts of your post were edited out.

[kkennedy91]

and also the NaCl which was 1.0x10-3

My bad it was 9.99x10^-3 So I just find the Mols of BaCl2 and then NaCL and add them together? that comes out to 0.0153.  Correct answer is apparently 0.017mol/l.  Im really sorry

[AWK]

How many moles of Cl is in 1 mol BaCl₂? And how many ... is in 3.51·10^-3?

[kkennedy91]

2 mols. I think?  theres two atoms of chlorine contained.

[kkennedy91]

How many moles of Cl is in 1 mol BaCl₂? And how many ... is in 3.51·10^-3?

wow...im a dummy.  Thank you.  Im sorry.  1st year chemistry.  Havent done any chemistry in 7 years so its slowly coming back....very slowly.