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Topic: Vanadium half reactions  (Read 2756 times)

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Offline sun725

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Vanadium half reactions
« on: October 30, 2016, 11:06:59 AM »
Hi,

I have to write the equations for the three redox reactions in the oxidation state of vanadium.

I started by writing the half reactions, and I wonder if they're correct?

V2+ → V3+ 
VO2+ → V3+ + H2
VO2+ + 2H+ → V3+ + H2
VO2+ + 2H+ + e- → V3+ + H2

Thanks in advance

Offline AWK

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Re: Vanadium half reactions
« Reply #1 on: October 30, 2016, 11:17:54 AM »

VO2+ + 2H+ + e- → V3+ + H2O

Check material and charge balance
AWK

Offline sun725

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Re: Vanadium half reactions
« Reply #2 on: October 30, 2016, 11:38:03 AM »
So it should be:

VO2+ + 2H+ + e- → H2O(l) +VO2+(aq)

Thanks again

Offline AWK

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Re: Vanadium half reactions
« Reply #3 on: October 30, 2016, 12:12:06 PM »
This particular reaction is correct but it has nothing common with your previous reactions.

Since almost all reactions chemist perform in water you may omit (i) and (aq) or use these symbols consequently on both side of reaction (for electrons this is unusable).
AWK

Offline sun725

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Re: Vanadium half reactions
« Reply #4 on: October 30, 2016, 12:19:33 PM »
Okay,

I tried again and came up with this:

e-+2H++VO2+ :rarrow: VO2++H2O

Offline AWK

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Re: Vanadium half reactions
« Reply #5 on: October 30, 2016, 01:35:05 PM »
This is the same reaction as previously (more consistent, since without additional symbols).
THe first your reaction was:
Quote
V2+ → V3+
 
probably V(V)
V(V)  :rarrow: V(III)
then
VO2+  :rarrow: VO+

and finally you presented reaction for
V(V)  :rarrow: V(IV)
AWK

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