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Author Topic: Redox reaction  (Read 1504 times)

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uncreative

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Redox reaction
« on: December 24, 2016, 04:40:21 AM »

KMnO4+ HCl --> KCl+ MnCl2 + H2O + Cl2


Can you tell me how to balance this reaction?
I know the half reaction method, But to me it doesn't work here!
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AWK

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uncreative

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Re: Redox reaction
« Reply #2 on: December 24, 2016, 06:25:37 AM »

Ok thank you
instead if I want to balance this equation

HNO3 + C2H6O + K2Cr2O7 -->  KNO3 + C2H4O + H2O + Cr(NO3)3

so first thing first

This is what I think, please tell me where I do wrong.

Carbon: n.o. from -2 ( in C2H6O) to -1 ( in C2H4O) so it gets oxidized


Chromium: n.o. from +6 (  in K2Cr2O7) to +3 ( in Cr(NO3)3)  so it gets reduced


Now, I have troubles in writing the 2 half reaction

For example, when I write the half reaction for oxidation, which has carbon, do I have to write the entire formula ( C2H6O) or just carbon or carbon and oxyxen?
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Re: Redox reaction
« Reply #3 on: December 24, 2016, 08:05:57 AM »

http://www.periodni.com/balancing_redox_equations.php
put equation in form
HNO3 + C2H6O + K2Cr2O7 = KNO3 + C2H4O + H2O + Cr(NO3)3
and you will get automatic solution with detailed explanation
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uncreative

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Re: Redox reaction
« Reply #4 on: December 24, 2016, 08:22:36 AM »

Oh this is awesome man! Thanks a lot
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