Lol, sorry for forgetting the C in acetic acid. Ya so a friend of mine told me that we don't need to include the Na part of the NaOH.
So then it would just be CH3COOH + OH = CH3 COO- + H2O
Now i'm just wondering.. Question is ..
When a weak acid is titrated using a strong base as the titrant, the titrated mixture will be basic at the equivalence point. Based on the equation i put above, why is this true??
Attempt: My guess is that . the reaction won't go all the way to the way forward. Cause it's not a strong acid on the reactants side, and the equilibrium is at the equivalence point. (So does a weak acid always mean it's on the basic side when confronted with a strong base?)