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Topic: Percent Yield/Stoichiometry etc.  (Read 1497 times)

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Offline mycattypes

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Percent Yield/Stoichiometry etc.
« on: February 02, 2017, 06:11:30 PM »
Hi there, I have a question about a very important chemistry homework question I have.
Would someone please be able to solve this and give me an explanation as to how you came about your answer? I would be so grateful. Thanks!
Consider the reaction
CaCN2 + 3 H2O → CaCO3 + 2 NH3 ,
which has a 45.6% yield. How much H2O is
needed to produce 16.3 moles of CaCO3?
1. 107 g
2. 22.3 g
3. 48.9 g
4. 1930 g
5. 880 g
6. 401 g

Offline AWK

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Offline Hunter2

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Re: Percent Yield/Stoichiometry etc.
« Reply #2 on: February 03, 2017, 12:44:43 PM »
Hi there, I have a question about a very important chemistry homework question I have.
Would someone please be able to solve this and give me an explanation as to how you came about your answer? I would be so grateful. Thanks!
Consider the reaction
CaCN2 + 3 H2O → CaCO3 + 2 NH3 ,
which has a 45.6% yield. How much H2O is
needed to produce 16.3 moles of CaCO3?
1. 107 g
2. 22.3 g
3. 48.9 g
4. 1930 g
5. 880 g
6. 401 g

1. Check according the equation how much mole water correspondes to the Calciumcarbonate , calculate this to the given moles.
2. Convert this to the mass
3. Calculate value with the yield

Now its yout turn

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