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Topic: Methane Stoichiometry  (Read 11338 times)

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Online Borek

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Re: Methane Stoichiometry
« Reply #15 on: February 15, 2017, 02:57:04 AM »
So the answer would be 6.3*10-3 liters of Oxygen?

Yes. If we are at it - try to convert it to mL.
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Offline Vultux

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Re: Methane Stoichiometry
« Reply #16 on: February 15, 2017, 06:59:29 AM »
Would it be just 6.3 ml of Oxygen?

also could you help me with this part to the question. I'm confused on how to setup the problem with the methane one.

If the reactant present in the least amount were to be quadrupled, how many grams of each product would be made.
« Last Edit: February 15, 2017, 08:13:56 PM by Arkcon »

Offline sjb

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Re: Methane Stoichiometry
« Reply #17 on: February 15, 2017, 10:29:44 AM »
yes 6.3 ml of oxygen.

What reactant is present in the least quantity? What is 4 times that? Re-evaluate limiting reagents for the reaction with this in mind.

Offline Vultux

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Re: Methane Stoichiometry
« Reply #18 on: February 15, 2017, 04:46:42 PM »
Would that be CH4? Just basing on the coefficients as I'm not sure what it's supposed to be based on.
« Last Edit: February 15, 2017, 05:05:31 PM by Vultux »

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Re: Methane Stoichiometry
« Reply #19 on: February 15, 2017, 05:25:24 PM »
If the reactant present in the least amount were to be quadrupled, how many grams of each product would be made.

Question is not clear to me. I am not sure if it is intended to mean "If the reactant present in the least amount were to be quadrupled without changing amount of the other reactant" or "If the reactant present in the least amount were to be quadrupled and the other reactant is in excess". These are two completely different problems.

I guess it is intended to be a limiting reagent type problem, just poorly worded.
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Offline Vultux

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Re: Methane Stoichiometry
« Reply #20 on: February 15, 2017, 05:35:07 PM »
What would be the limiting reagent in this equation? also how would I find out the amount of grams the products would make?

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Re: Methane Stoichiometry
« Reply #21 on: February 15, 2017, 06:52:18 PM »
What would be the limiting reagent in this equation?

What is a limiting reagent doesn't depend on the reaction, it depends on the relative amounts of substances present. Have you tried to google the term and read?

Quote
also how would I find out the amount of grams the products would make?

How do you convert moles to mass?
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Offline Vultux

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Re: Methane Stoichiometry
« Reply #22 on: February 15, 2017, 07:28:14 PM »
I understand what the limiting reagent is, just confused on how to find the mole/gram without some starting point.

To go from moles to mass, you multiply the amount of moles by the molar mass.

Offline hypervalent_iodine

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Re: Methane Stoichiometry
« Reply #23 on: February 15, 2017, 07:30:11 PM »
Is the starting point not in the question you posted in your OP, and in the answer you came to for the first question? Or is there something else you aren't posting?

Offline Vultux

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Re: Methane Stoichiometry
« Reply #24 on: February 15, 2017, 07:35:31 PM »
It's a addition to the question. ""If the reactant in the least amount were to be quadrupled, how many grams of each product would be made?"

Offline hypervalent_iodine

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Re: Methane Stoichiometry
« Reply #25 on: February 15, 2017, 07:42:06 PM »
It's a addition to the question. ""If the reactant in the least amount were to be quadrupled, how many grams of each product would be made?"

Right, so the assumption then is you use the amounts you used in the prior question.

Offline Vultux

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Re: Methane Stoichiometry
« Reply #26 on: February 15, 2017, 07:49:02 PM »
But how would I convert them without some sort thing to convert it with

Offline hypervalent_iodine

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Re: Methane Stoichiometry
« Reply #27 on: February 15, 2017, 07:54:00 PM »
But how would I convert them without some sort thing to convert it with

I don't understand your question. Convert what to what?

Offline Vultux

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Re: Methane Stoichiometry
« Reply #28 on: February 15, 2017, 08:00:52 PM »
For limiting reagents, don't I have to convert them to moles to find out which runs out first or something? I have no idea what I'm doing to be honest.

Offline hypervalent_iodine

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Re: Methane Stoichiometry
« Reply #29 on: February 15, 2017, 08:02:15 PM »
For limiting reagents, don't I have to convert them to moles to find out which runs out first or something? I have no idea what I'm doing to be honest.

Did you not calculate this in the question before hand?

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