March 28, 2024, 10:57:52 AM
Forum Rules: Read This Before Posting


Topic: g/ml -> g/L  (Read 3405 times)

0 Members and 1 Guest are viewing this topic.

Offline wm334

  • Regular Member
  • ***
  • Posts: 22
  • Mole Snacks: +0/-0
  • Gender: Male
g/ml -> g/L
« on: March 01, 2017, 04:35:19 AM »
If I make a 0.2g/ml solution and dissolve this in 1L, do I have 0.2g/L?

Thanks

Offline mjc123

  • Chemist
  • Sr. Member
  • *
  • Posts: 2049
  • Mole Snacks: +296/-12
Re: g/ml -> g/L
« Reply #1 on: March 01, 2017, 04:38:22 AM »
How much of the 0.2 g/ml solution do you have?

Offline wm334

  • Regular Member
  • ***
  • Posts: 22
  • Mole Snacks: +0/-0
  • Gender: Male
Re: g/ml -> g/L
« Reply #2 on: March 01, 2017, 04:52:02 AM »
5 ml

Offline DrCMS

  • Chemist
  • Sr. Member
  • *
  • Posts: 1296
  • Mole Snacks: +210/-81
  • Gender: Male
Re: g/ml -> g/L
« Reply #3 on: March 01, 2017, 05:24:22 AM »
So if you have 5ml of 0.2g/ml solution how many grams of this substance are there?  If you make that up to 1L does that change how man grams of of the active are in the 1L solution?

Offline wm334

  • Regular Member
  • ***
  • Posts: 22
  • Mole Snacks: +0/-0
  • Gender: Male
Re: g/ml -> g/L
« Reply #4 on: March 01, 2017, 05:51:54 AM »
I think I still have 2g in both solutions, but I know if I look at molartiy this changes.

Offline DrCMS

  • Chemist
  • Sr. Member
  • *
  • Posts: 1296
  • Mole Snacks: +210/-81
  • Gender: Male
Re: g/ml -> g/L
« Reply #5 on: March 01, 2017, 06:45:49 AM »
What is 5x0.2? 

Offline wm334

  • Regular Member
  • ***
  • Posts: 22
  • Mole Snacks: +0/-0
  • Gender: Male
Re: g/ml -> g/L
« Reply #6 on: March 01, 2017, 06:48:34 AM »
1

Offline Arkcon

  • Retired Staff
  • Sr. Member
  • *
  • Posts: 7367
  • Mole Snacks: +533/-147
Re: g/ml -> g/L
« Reply #7 on: March 01, 2017, 07:06:05 AM »
I think I still have 2g in both solutions, but I know if I look at molartiy this changes.

You know the grams, and you know the old an new volumes.  How does it change?

First think: you start with some amount, you add more solvent, your final answer has to be less than it was before?

Also think, by how much less:  If you had a gram, in 10 mL, and you added 90 ml more ... you'd have the same gram, but now in 100.  The 100 is different from 10 by how?

Please try to put all your work, from start to finish, in one posting.  Otherwise the thread will grow to multiple pages, and we'll forget what we've already done.
Hey, I'm not judging.  I just like to shoot straight.  I'm a man of science.

Offline wm334

  • Regular Member
  • ***
  • Posts: 22
  • Mole Snacks: +0/-0
  • Gender: Male
Re: g/ml -> g/L
« Reply #8 on: March 01, 2017, 07:29:14 AM »
OK I presume 0.2g/5ml, use c1v1.. 0.2*5/1000 ml, new concentration = 0.001g/L

Offline AWK

  • Retired Staff
  • Sr. Member
  • *
  • Posts: 7981
  • Mole Snacks: +555/-93
  • Gender: Male
Re: g/ml -> g/L
« Reply #9 on: March 01, 2017, 07:37:04 AM »
If I make a 0.2g/ml solution and dissolve this in 1L, do I have 0.2g/L?
Quote
I presume 0.2g/5ml
Which is correct?
AWK

Offline wm334

  • Regular Member
  • ***
  • Posts: 22
  • Mole Snacks: +0/-0
  • Gender: Male
Re: g/ml -> g/L
« Reply #10 on: March 01, 2017, 07:41:36 AM »
0.2g/5ml

Offline AWK

  • Retired Staff
  • Sr. Member
  • *
  • Posts: 7981
  • Mole Snacks: +555/-93
  • Gender: Male
Re: g/ml -> g/L
« Reply #11 on: March 01, 2017, 07:48:23 AM »
You informed us that your concentration is 0.2 g/ml. Then you added that you have 5 ml of solution.
This means that you dilute 5 ml of solution with concentration of 0.2 g/ml to 1000 ml (1L). In such a case your answer is wrong.
Or you something changed during discussion?
AWK

Offline wm334

  • Regular Member
  • ***
  • Posts: 22
  • Mole Snacks: +0/-0
  • Gender: Male
Re: g/ml -> g/L
« Reply #12 on: March 01, 2017, 08:16:25 AM »
ok 0.2g/ml is 0.0002g/L using C1V1

Offline AWK

  • Retired Staff
  • Sr. Member
  • *
  • Posts: 7981
  • Mole Snacks: +555/-93
  • Gender: Male
Re: g/ml -> g/L
« Reply #13 on: March 01, 2017, 08:23:45 AM »
OK, this is a simple 1000 times dilution.
AWK

Offline KungKemi

  • Regular Member
  • ***
  • Posts: 64
  • Mole Snacks: +3/-1
  • Gender: Male
Re: g/ml -> g/L
« Reply #14 on: March 04, 2017, 04:47:18 AM »
They have an equation for such scenarios as that known as the "Dilution Equation". The equation states that if moles - or mass in your instant - of solute is kept constant then the following is true:

C1V1 = C2V2

where C1 is the original concentration of solution, and V1 is original volume of solution, and C2 is final concentration of diluted solution, and V2 is final volume of diluted solution.

You know all but final concentration (in g/mL) - rearrange to find final concentration.
KungKemi

Sponsored Links