A book I'm reading gives an example of a reaction between acetic acid and ethanol. It says that if 1 mole of each is used that there is .66 moles of ethyl acetate produced. Putting this into the equilibrium equation gives (.33 water)(.33 ethyl acetate)/(.17 ethanol)(.17 acetic acid) = 3.77.
They then say that by increasin the amount of ethanol to 2 moles that the amount of ethyl acetate can be calculated using the KE of 3.77.
Could someone explain how this calculation is done?
Thanks.