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Topic: Molar heat capacity of calcium phosphate  (Read 2571 times)

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Offline long-live-mercutio

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Molar heat capacity of calcium phosphate
« on: November 09, 2017, 06:59:42 AM »
Hello everyone!
 
This is the equation that describes the temperature dependence of calcium phosphate's heat capacity:
 
Сp = 203,3 + 170,1*10–3 Т – 26,11*105 Т –2 J/(mol*K)
 
in the  273 - 1 373 К temperature interval. What is the ΔH of the heating reaction of calcium phosphate from 600 to 900 K?
 
The answer is 97.8 kJ, but the only answer I can get after integration is

 203.3 (900-600) + (170.1*10-3/2)(9002-6002)+26.11*105*(1/900-1/600) = 93.460  kJ.

The problem doesn't state the amount of calcium phosphate, so I've been wondering if that's the reason why the answers don't match - should I find the amount of mol, instead of just assuming it's 1 mol? But I can't come up with a way to do so:( Could you help me please?





I have made the calculations again and everything is okay now! Sorry, my bad:)

Offline Corribus

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Re: Molar heat capacity of calcium phosphate
« Reply #1 on: November 09, 2017, 12:23:55 PM »
Are you sure you did your arithmetic right? I got 97811 J (97.811 kJ) when I used your equation.
(Term 1 ~ 60990 J, Term 2 ~ 38272 J, Term 3 ~ -1451 J)
What men are poets who can speak of Jupiter if he were like a man, but if he is an immense spinning sphere of methane and ammonia must be silent?  - Richard P. Feynman

Offline long-live-mercutio

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Re: Molar heat capacity of calcium phosphate
« Reply #2 on: November 10, 2017, 02:47:24 AM »
Yes, I have done it again and everything was correct, thank you!

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