I am trying to synthesis a hydroxymethyl imidazole following a literature procedure.
J. Chem. Soc., Perkin Trans. 1, 1997,0, 2203-2210.
My understanding of this imidazole formation mechanism is through loss of two water molecules to get a alkene intermediate. This intermediate further hydrolysis under acidic condition to for a hydroxymethyl imidazole.
Am I understand this mechanism correctly?
I tried reaction by mixing trifluoroacetamidine and butane-2,3-dione in water and stirred at R.T. overnight.
I am also trying neat reaction at 60 degree C.
Nothing happened so far.
Is there any suggestions?
Thanks a lot.