I am having trouble writing the reduction of Cu2+ by NH2OH in acid solution.
This is what I have right now now:
4Cu^2+ +2NH_2OH --> 4Cu^1+ + N_2O + H_2O + 4H^+
My other question is regarding this: "At a pH of 4, the Cu-neocuproine complex formed in the liquid-liquid extraction experiment has a partition coefficient of about 6.4 when equilibrated between the acid aqueous solution and chloroform. Calculate the concentration of Cu in the chloroform phase if 39.0 mL of a 0.27 M aqueous Cu solution buffered to pH 4 is equilibrated with 14.0 mL of chloroform."
Im not sure where to start, and how to use the pH in this relation.