[RespectfulStudent]

Hi,I have a chemistry homework question that has confused me:

Original Question for which I am seeking assistance:

In step 3 of the procedure, the vinegar is diluted. If the vinegar was not diluted, what volume of titrant would have been required to neutralize the acid? Why might this be a problem?

Step three of the procedure:

Obtain a 5mL pipet and measure out 5.0 mL of vinegar into a clean 100mL volumetric flask. Then dilute wit water to the 100 mL mark. Use a beral pipet for the last few mL.

The vinegar contained acetic acid, HC₂H₃O₂.

original dilution factor= 1/20 (when simplified, otherwise 5mL/100mL)[/li][/list]

Note: The vinegar was diluted by someone other than myself

What I don't understand:
>>>> if the vinegar is not diluted (see the original question), does that mean that no water is added? Ie.  5mL vinegar/0 mL water rather than 5mL vinegar/100mL water?
Thanks,
RespectfulStudent

[Babcock_Hall]

As far as I am concerned, if a sample is has not been diluted, then it means that no water was added.