Thanks for your reply...it has been very helpful. However, i found out that the experiment conducted for one of the reactants have to be in excess. Hence. the experiment have to be done twice for each reactant(in excess).
What i'm afraid is that the conductivity measured, includes the excess e.g(NaOH) that was not reacted. Therefore, I'm not sure whether the method/equation given by you is applicable.
For the experiment, I have to set the concentration of the reactants [NaOH] :[CH3COOC2H5] to the ratio of 1:5 respectively and vice versa. Hence, I have to use the method of excess to calculate the rate law.
If thats the case, how to find the conductivity of each reactant from the conductivity total?
I am supposed to calculate the conductivity of NaOH and conductivity of NaAc using the eqn below,
Conductivity total=conductivity of NaOH + conductivity of NaAc
conductivity of NaOH = 0.195[1+0.0184(T-194)][NaOH]
conductivity of NaAc = 0.07[1+0.0284(T-194)][NaAC]
And since one of the reactants ( NaOH ) is in excess, which reactant (NaOH or CH3COOC2H5) should I put in first so as not to spoil the conductivity meter?