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Topic: Redox equation  (Read 3751 times)

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Alfred

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Redox equation
« on: July 06, 2006, 11:29:42 AM »
If 4 cm3 potassium manganate(VII) is needed for 25cm3 hydroxyammonium sulphate+25cm3 dilute sulphuric acid.
 How to calculate
a)concentration(mol dm-3) of ion MnO4-
b)concentration of ion Fe2+ in solution of hydroxyammonium sulphate with excess iron(III) ammonium sulphate and dilute sulphuric acid
c)mass of ion iron(II) in 1 dm3 of hydroxyammonium sulphate with excess iron(III) ammonium sulphate and dilute sulphuric acid
d)no moles of iron (II) ions required to oxidise 1 mol of hydroxyammonium ion.

Instead of giving Fe3+ + 2 NH3OH+  + 2H+ + 5e- --> Fe2+ + N2O + H2O + 4 H2
My teacher gives us this one 4 Fe3+ + 2 NH3OH+ --> 4 Fe2+ + N2O + H2O + 6H+

Offline AWK

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Re: Redox equation
« Reply #1 on: July 07, 2006, 06:07:12 AM »
You should know at least one concentration  (Fe3+)
AWK

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