[ockzy]

If you add 50gr Zn dust to solution, after adding 1M 600cm³ NaOH solution to 2M 400cm³ H₂SO₄ solution and wait long enough. What percentage of 50gr Zn enters to reaction?

​

(Zn: 65gr/mole)

​

The answer is 65% but cant figure it out exactly. Can someone help me up?


My attempt: 1,6 mole H+ / 0,8 mole SO4 / 0,6 mole OH / 0,6 mole Na:

OH and H+ reacts and we are left with 1mole H+ and no OH:

ZnSO4 ---> Zn + SO4 both used 0,8 mole. 52gr more than we started with :/ so all of it can be used as how i calculated

[Babcock_Hall]

Please show your work (that is a Forum Rule); then someone may be able to help you.

[ockzy]

Please show your work (that is a Forum Rule); then someone may be able to help you.

1,6 mole H+ / 0,8 mole SO4 / 0,6 mole OH / 0,6 mole Na:

OH and H+ reacts and we are left with 1mole H+ and no OH:

ZnSO4 ---> Zn + SO4 both used 0,8 mole. 52gr more than we started with :/ so all of it can be used as how i calculated

[mjc123]

ZnSO4 ---> Zn + SO4 both used 0,8 mole

This reaction does not occur in your system.
What is the reaction that Zn undergoes here?