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Topic: Density problem  (Read 4456 times)

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AmberLynn

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Density problem
« on: September 01, 2004, 10:18:31 PM »
An irregularly shaped piece of lead weighs 10.0g It is carefully lowered into a graduated cylinder containing 30mL of ethanol, and it sinks to the bottom of the cylinder. To what volume does the ethanol rise?   :-\ i need it by 12 am tonight
« Last Edit: September 05, 2004, 11:18:05 PM by hmx9123 »

Tetrahedrite

  • Guest
Re:How do i solve this?!
« Reply #1 on: September 01, 2004, 10:31:22 PM »
This is a simple volume-density question. The ethanol will rise by the volume of the lead. This can be simply calculated using the equation volume = mass/density. My SI data book gives the density of lead at 11.4g/cm3

AmberLynn

  • Guest
Re:How do i solve this?!
« Reply #2 on: September 01, 2004, 10:50:19 PM »
yea, but i still dont get it.... it gives me a choice of 4 answers it could be, and i'm not getting any one of them. The 4 answers are a)31.9 b)30.9 c) 31.2 d0 30.2
 d=m/v so... d=10.0/30.0 and that gives me .33 repeating which isnt right. I'm so lost please help  :'(

Tetrahedrite

  • Guest
Re:How do i solve this?!
« Reply #3 on: September 02, 2004, 12:12:06 AM »
It has nothing to do with the volume of the ethanol, the same question could be asked with water or chloroform etc. All that is required is the volume of the piece of lead. This is equal to mass/density = 10.0/11.4 = 0.88cm3 = 0.88mL. So the volume of the ethanol will be increased by 0.88, Therefore the answer is 30 + 0.88 = 30.88mL

ssssss

  • Guest
Re:How do i solve this?!
« Reply #4 on: September 02, 2004, 06:10:22 AM »
It has nothing to do with the volume of the ethanol, the same question could be asked with water or chloroform etc. All that is required is the volume of the piece of lead. This is equal to mass/density = 10.0/11.4 = 0.88cm3 = 0.88mL. So the volume of the ethanol will be increased by 0.88, Therefore the answer is 30 + 0.88 = 30.88mL

Yeah just the Archemedis Principle.

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