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Topic: How does zirconium oxynitrate idrate transform into zirconium hydroxide?  (Read 2582 times)

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Offline Mustungun

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Hi everyone. I'm doing an internship at my university in the industrial chemistry branch. I'm currently working on a hard template synthesis of zirconium hydroxide.
I know the precursor is ZrO(NO3)2 * 6H2O and it somehow becomes Zr(OH)4, which is needed for the sulphation process. Though, the calcination needed to remove the template transforms it into ZrO2, which is kinda problematic for the sulphation, but I digress. I'm trying to figure out how should I write the reactions. I have an hypothesis, but I can't confirm it for myself. Can you confirm it for me, or correct me if I'm wrong? Thank you in advance for your time.

2ZrO(NO3)2* 6H2O + 4NaOH + 4H2O + O2 ---> 2Zr(OH)4 * 6H2O + 4NaNO3

Zr(OH)4*6H2O ---> ZrO2 + 8H2O

Offline chenbeier

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Re: How does zirconium oxynitrate idrate transform into zirconium hydroxide?
« Reply #1 on: November 14, 2018, 10:37:13 AM »
I would eleminate some water in your equations. Zirconiumhydroxide will not carry 6 water.

Offline Mustungun

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Re: How does zirconium oxynitrate idrate transform into zirconium hydroxide?
« Reply #2 on: November 14, 2018, 11:03:03 AM »
You're right. Does the rest seem to be correct?

Offline chenbeier

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Re: How does zirconium oxynitrate idrate transform into zirconium hydroxide?
« Reply #3 on: November 14, 2018, 02:04:01 PM »
The equations i still not ok, because there is no redox reaction. Zirconium stays with oxidation number 4. So you dont need oxygen as well.

Offline Mustungun

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Re: How does zirconium oxynitrate idrate transform into zirconium hydroxide?
« Reply #4 on: November 15, 2018, 07:36:01 AM »
ZrO(NO3)2*6H2O + 2NaOH ---> Zr(OH)4 + 5H2O + 2NaNO3

How's this?

Offline chenbeier

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Re: How does zirconium oxynitrate idrate transform into zirconium hydroxide?
« Reply #5 on: November 15, 2018, 07:58:11 AM »
Sound good.

Offline Mustungun

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Re: How does zirconium oxynitrate idrate transform into zirconium hydroxide?
« Reply #6 on: November 16, 2018, 09:19:37 AM »
Perfect. Thank you alot.

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