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Author Topic: How to derive ΔG∘=−RTlnKeq from ΔG∘= ΔH∘-T ΔS∘?  (Read 859 times)

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AussieKenDoll

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How to derive ΔG∘=−RTlnKeq from ΔG∘= ΔH∘-T ΔS∘?
« on: December 19, 2018, 05:26:33 PM »

How to derive ΔG∘=−RTlnKeq from ΔG∘= ΔH∘-T ΔS∘?
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AussieKenDoll

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How to derive ΔG∘=−RTlnKeq from basic thermodynamic principles?
« Reply #1 on: December 19, 2018, 05:28:08 PM »

How to derive ΔG∘=−RTlnKeq from basic thermodynamic principles?
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Borek

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Re: How to derive ΔG∘=−RTlnKeq from ΔG∘= ΔH∘-T ΔS∘?
« Reply #2 on: December 19, 2018, 09:07:34 PM »

I have merged your threads as they are very similar.

You have to show your attempts at answering the question before receiving help, this is a forum policy.

Have you tried to google?
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