It looks to me like ammonium nitrate (NH4
) will dissociate in water into NH4+
. I calculated the pH using the provided acid dissociation constant for NH4+
and got the answer pH = 5.13. This is correct, as per the answer key, so it seems that I used the correct procedure.
Still, I am confused. It seems to me like the solution contains a stronger base than water, NO3-
. I am trying to understand why the calculation is done without factoring in this in, as if we were just dealing with NH4+
(aq). The calculation, which yields the correct answer, uses the equation NH4+
(aq) + H2
. Why is the presence of NO3-
in the solution not taken into consideration?