It is the same The electrons from both Hydrogen are catched by the Oxygen.
The exchange can take place in this way
As 2 H2 + O2 => 2 H2O
H2 + F2 => 2 HF
or 2 Na + 2 H2O => 2 NaOH + H2
NaOH + HF => NaF + H2O
The reult is in both case the same. The electron exhange takes place, if the elements react each other.
In the equation 2 Na + 2 H2
2 NaOH + H2
, Na gives its single valence electron to OH and forms an ionic bond. In H2
2 HF, the F2
splits and shares one electron with H to form the HF molecule. In 2 H2
O Hydrogen atoms split from each other, each having one valence electron, then bind to the oxygen atom, with oxygen providing one electron and the hydrogen providing the other.
But in NaOH(s) + HF(g)
NaF(s) + H2
I) HF splitting into H+
and NaOH into Na+
before the formation of water and salt, then the H+
that split from the HF has no electrons to share with OH-
so the oxygen has to provide both of the electrons to form the covalent bond. Is this true or not, this is precisely what I'm asking.
II) You said there is an electron exchange, but when the NaF(s) forms, Na+
ions are already stable. How do they exchange electrons? Or do they form an ionic bond without the electron exchange?