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### Topic: A compound containing titanium (Ti) and chlorine is analyzed by  (Read 5265 times)

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#### funboy

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##### A compound containing titanium (Ti) and chlorine is analyzed by
« on: August 03, 2006, 09:49:01 AM »
A compound containing titanium (Ti) and chlorine is analyzed by converting all the titanium into 1.20 g of TiO2 and all the chlorine into 6.45 g of AgCl.  What is the simplest formula for the original compound?

Mol of TiO2    = 1.20 / 79.9   = .015 mol
Mol of AgCl    = 6.45/143.4   = .045 mol

So

Moles of Ti atoms    = .015
Moles of O2 atoms   = .030
Moles of Ag and Cl   = .045

The above is a 1:2:3 ratio

So TiCl would have an empirical formula of TiCl3
« Last Edit: August 03, 2006, 03:16:43 PM by Mitch »

#### Albert

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##### Re: Is this correct??
« Reply #1 on: August 03, 2006, 10:15:58 AM »
Yes, it looks correct.