A compound containing titanium (Ti) and chlorine is analyzed by converting all the titanium into 1.20 g of TiO2 and all the chlorine into 6.45 g of AgCl. What is the simplest formula for the original compound?
Mol of TiO2 = 1.20 / 79.9 = .015 mol
Mol of AgCl = 6.45/143.4 = .045 mol
Moles of Ti atoms = .015
Moles of O2 atoms = .030
Moles of Ag and Cl = .045
The above is a 1:2:3 ratio
So TiCl would have an empirical formula of TiCl3