Hello,

How much N_{2} can be solved in 1L of water at 20 celsius, 1 atm total pressure, if the partial pressure of the N_{2} gas is 0.78atm? From a table I found that the solubility of N_{2} in water at 20 celsius is 0.0190 g/L, at a total pressure of 1 atm. The solution manual calculates it this way:

0.78atm*0.0190 g/L = 0.01482 g/L. But is this correct? From how I understand the task the answer should just be 0.0190 g/L