This is my first post so please bash me if I format something wrong.
This is Experimental Chem/Principles of Chem if that helps.
Use the moles of CO2 produced to determine the mass (g) of carbon present in NaHCO3.
Moles of CO2: 6.90x10-5
Mass of reactant (NaHCO3): 0.0864 g
Overall Equation: NaHCO3(s) + H2SO4(aq) ➞ H2O(l) + CO2(g) + NaHSO4(aq)
I would think that since the mol ratio of CO2 and NaHCO3 is 1:1, then 6.90x10-5 moles of carbon is present in NaHCO3 and then just use the molar mass of C to determine the mass in grams. Right?