We did a lab yesterday and here are the results:
Pb(NO3)2+ 2KI → 2KNO3 + PbI2
We had 0.95g of Lead (II) Nitrate and 1.10g of Potassium Iodide.
I've converted Pb(NO3)2 to Moles which gave me 0.00286 moles.
1.10g of KI2 are 0.00662 moles.
How do I find the limiting reagent and what are the steps specifically.