May 23, 2019, 03:24:35 PM
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Topic: Titration  (Read 199 times)

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Offline Al3x2012

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Titration
« on: March 17, 2019, 01:09:33 PM »
Recently in my chemistry class, we have learned about how titration works. The teacher then proceeded to teach us to to calculate the concentration of the acid(used in the titration) from the already know concentration of the base. Sadly i did not catch on the entire process. Is there someone who can explain to me how to calculate the concentration of the acid if the concentration of the base is known?
Thank you.

Offline Borek

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Re: Titration
« Reply #1 on: March 17, 2019, 01:47:40 PM »
Simple stoichiometry and direct application of the concentration definition.

http://www.titrations.info/titration-calculation
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Offline MargaaMarius

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Re: Titration
« Reply #2 on: March 18, 2019, 06:07:04 AM »
We've just done the same, but we only used strong acids/bases as titrants. When you use strong titrants, the equivalence point is when the amount of tirtant you have used equal the amount of acid/base in the sample before you did the titration. So let's say that you used 20 mL 0,1 mol/L NaOH to get the equivalence point. 0,020L * 0,1mol/L = 0,002 mol. You had 0,002 mol acid in your sample. Let's say the sample size was 10mL, then the concentration was 0,002mol/L / 0,010 L = 0,2 mol/L.

Offline AWK

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Re: Titration
« Reply #3 on: March 19, 2019, 08:12:25 AM »
There is a very simple formula:
c1V1=c2V2
This is equation with one unknown.

Correction of subscripts
« Last Edit: March 19, 2019, 09:39:06 AM by AWK »
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