Okay, let me just write down the question I'm looking at first.
"When a 6.50g sample of solid sodium hydroxide dossolves in 100.0 g of water in a "coffee cup" calorimeter, the temperature rises from 21.6 degrees C to 37.8 degrees C. Calculate the change in heat (the letter H with a triangle to the left of it) for the solution process:
NaOH(s) -> Na+(aq) + OH-(aq)
Assume that the specific heat of the solution is the same as that of pure water.
Okay, so I know that you have to turn degrees Celsius into Kelvins, which brings it up to 294.6K and 310.8K. And the specific heat of water is 4.184 J.g-1.K-1. However, I do not know how to apply that to the chemical equation that was presented in the equation.
I know this is my first post, and some forums look down on that (or so I hear, I dunno, I don't spend much time in forums). Please, though. I do need the help. Thanks.