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#### natalie5933

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« on: January 22, 2022, 01:46:29 PM »
Question-
A standardization experiment was completed for the following reaction: S and P were mixed and the H NMR was taken. For the aromatic singlet closest to the ester, the integration were S=1.133 and P = 0.923. This same mixture was injected onto an HPLC and a ration of S:P = 36.7:63.3 was seen (based on peak integrations).
By what factor (response factor) do I need to multiply the starting material to get correct molar ratios for S:P?

Doubts-
what does nmr integration have to do anything with molarity?

« Last Edit: January 22, 2022, 03:50:11 PM by natalie5933 »

#### Babcock_Hall

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« Reply #1 on: January 22, 2022, 03:42:05 PM »
What do you know about NMR integration?

#### natalie5933

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« Reply #2 on: January 22, 2022, 03:42:52 PM »
That it tells you the number of protons

#### natalie5933

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« Reply #3 on: January 22, 2022, 04:53:18 PM »
So I have edited the post to show you the pic. Now correct me if I am wrong. acc to the structures and considering I am just the using the singlet signal close to the ester. so the number of protons of A:B will be 1: 2 right? and then integral A:B after setting A to 1 will be 1:0.815 . So finally my ratio of compounds will be A:B = 1: 0.4075? is this correct??

#### Orcio_87

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« Reply #4 on: January 22, 2022, 05:35:58 PM »
Quote
So finally my ratio of compounds will be A:B = 1: 0.4075? is this correct??
Correct.. but why does the HPLC experiment give different result (P is the major product) ?

I think that H-NMR is not the best method for that type of quantitative measure, because both compounds are very similiar.
I mean - the instrument must have very high resolution.

#### natalie5933

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« Reply #5 on: January 22, 2022, 06:14:10 PM »
Quote
Correct.. but why does the HPLC experiment give different result (P is the major product) ?

That's what even I can't understand. The problem said this is a standardization experiment. But what are they trying to standardize? NMR or HPLC??

#### Orcio_87

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« Reply #6 on: January 23, 2022, 05:34:56 AM »
As of H-NMR it is clear that peak integration is proportional to quantity of "S" and "P" (if instruments resolution is high enough), but HPLC - detectors dont measure quantity but rather properties of solution at given time - absorbance at given wave-length or change of conductivity or something else.

I mean - peak integration in HPLC is not the same as its quantity as it strongly depends on the type of the detector.

#### natalie5933

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« Reply #7 on: January 23, 2022, 04:20:08 PM »
Quote
I mean - peak integration in HPLC is not the same as its quantity as it strongly depends on the type of the detector

Can u explain again? I didn't get it. I am using UV-Vis for analysis for its measuring absorbance.

#### Orcio_87

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« Reply #8 on: January 23, 2022, 04:27:15 PM »
For example - Cu(NH3)4Cl2 will absorb more than CuCl2. Higher peak at the same concentration.

If detector is ill-suited some compounds can even leave the column undetected. Detector measures only some properties, not quantity (concentration).

#### natalie5933

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« Reply #9 on: January 23, 2022, 04:30:21 PM »
Okay so how do I go about calculating response factor? By what factor should I multiple my starting material to get correct molar ratios then?

#### Orcio_87

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« Reply #10 on: January 23, 2022, 04:43:56 PM »
Ratio of compounds S to P is 1: 0.4075 - this is the molar ratio already.

Standarization of HPLC....

36.7 x a = 1
63.3 x b = 0,4075

"a" and "b" are factors for HPLC quantitative standarization.

#### natalie5933

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« Reply #11 on: January 23, 2022, 05:46:04 PM »
okay. Ya even I did that. Thanks a lot for your help.

#### natalie5933

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« Reply #12 on: January 23, 2022, 05:53:53 PM »
THANKS A LOT FOR YOUR HELP !! One last thing, they have given retention time for S & P - S = 7.9 min, P(ent 1) = 11.0 min, P(ent 2) = 27.2 min. How do I calculate % conversion of product assuming no other by product is present?

#### Orcio_87

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