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Topic: Sodium acetate  (Read 3020 times)

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Offline Enceph

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Sodium acetate
« on: December 11, 2007, 03:36:11 PM »
Why when Sodium Acetate is formed, the H on the end of the Acetic Acid formula goes away?  Acetic Acid (CH3COOH), and it becomes CH3COONa, when Acetic Acid and Sodium bond
« Last Edit: December 11, 2007, 03:49:44 PM by Borek »

Offline Borek

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Re: Sodium acetate
« Reply #1 on: December 11, 2007, 03:48:39 PM »
What is an acid?
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Offline ARGOS++

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Re: Sodium acetate
« Reply #2 on: December 11, 2007, 04:13:32 PM »
Dear Enceph;

Let’s say it a little simpler to not stress/forget all or any definition of Acids and Bases:

The O-H bond of the Acid is by far the bond with the most ionic nature, and ionic bonds tend to dissociate in water to a certain amount:
      CH3CO-O-H    <----->    CH3CO-O-  +   H+    (H+ mostly written as H3O+)
Similar is true for the Me-O bond of the Sodium hydroxide:
      Na-O-H            <----->    Na+   +  HO-
But as the Equilibrium in water of :   
      H3O+  + HO-   <----->  2H2O(liq.)    lies very strong on the right side the “final” Salt Sodium Acetate is remaining in ionic form, and that’s also the “form” how you can isolate it.

I hope this may help to give you an Idea.

Good Luck!
                   ARGOS++

P.S.: Sorry to all them, they think this may be “drawn” too simplified!
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