June 15, 2024, 05:07:08 PM
Forum Rules: Read This Before Posting


Topic: Properties of Solutions  (Read 4531 times)

0 Members and 1 Guest are viewing this topic.

Offline munoz_m1

  • New Member
  • **
  • Posts: 5
  • Mole Snacks: +0/-1
Properties of Solutions
« on: January 27, 2008, 08:26:18 PM »
How would you prepare a .150 M solution of glucose in water? A 1.35 m solution of KBr in water? And a solution of methyl alcohol and water in which X of CH3OH is 0.150 and X of H20 is 0.85?

Pleeeeeeeease help me! I have a headache with all this=(


Offline enahs

  • 16-92-15-68 32-7-53-92-16
  • Retired Staff
  • Sr. Member
  • *
  • Posts: 2179
  • Mole Snacks: +206/-44
  • Gender: Male
Re: Properties of Solutions
« Reply #1 on: January 27, 2008, 09:48:25 PM »
You would put that amount of mols into 1 liter of water...


Offline Borek

  • Mr. pH
  • Administrator
  • Deity Member
  • *
  • Posts: 27701
  • Mole Snacks: +1804/-411
  • Gender: Male
  • I am known to be occasionally wrong.
    • Chembuddy
Re: Properties of Solutions
« Reply #2 on: January 28, 2008, 09:46:17 AM »
You would put that amount of mols into 1 liter of water...

More like "You will dissolve that amount of substance in such amount of water theat the solution volume is 1L".
ChemBuddy chemical calculators - stoichiometry, pH, concentration, buffer preparation, titrations.info

Offline CABAL

  • Regular Member
  • ***
  • Posts: 14
  • Mole Snacks: +0/-0
Re: Properties of Solutions
« Reply #3 on: January 28, 2008, 10:35:31 AM »
Hey!
Glucose is C6H12O6, so that is 180 g/mol. That gives 180g/mol x 0.150 = 27g
You add 27g and fill with water to the 1L mark (if you’re making a liter :))

You follow the same approach with the others

Thanks,

Nicholas

Sponsored Links