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Offline govibe

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Orbitals question
« on: February 04, 2008, 07:10:55 PM »
An ion having a 4+ charge and a mass of 49.9 amu has 2 electrons with principal quantum number n = 1, 8 electrons with n = 2, and 10 electrons with n = 3. Supply as many of the properties for the ion as possible from the information given. (Hint: In forming ions, the 4s electrons are lost before the 3d electrons.)

(a) What is the atomic number?
(b) What is the total number of s electrons?
(c) What is the total number of p electrons?
(d) What is the total number of d electrons?
(e) What is the number of neutrons in the nucleus?
(f) What is the ground-state electron configuration of the neutral atom?

HEre's what I tried. For (a), I added up all of the electrons they give, and the sum is 20. If there is a 4+ charge, then there must be 24 protons, so is 24 the answer?

For (b), if there are 2 electrons with principal quantum number n = 1, then there's only 1 s orbital, but how about the number of electrons? There is also what I had trouble with (b), (c), (d), (e)... (f), I don't really understand what it's asking.

Offline enahs

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Re: Orbitals question
« Reply #1 on: February 05, 2008, 07:53:18 AM »
A) is good.

There is more then 1 s orbital. The n = 1 has an s orbital, then n = 2 has an s orbital, then n = 3 has an s orbital.


http://www.fordhamprep.org/gcurran/sho/sho/lessons/lesson36.htm


Remember the hint also told you it has lost 4 s electron when forming the ion.


Offline AWK

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Offline govibe

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Re: Orbitals question
« Reply #3 on: February 05, 2008, 10:29:04 AM »
so is this an ion with an electron configuration? (like 1s2 2s2 2p4 type of thing?)

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