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Polar or Nonpolar (Determining Solubility)
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Topic: Polar or Nonpolar (Determining Solubility) (Read 6897 times)
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DiscreteW
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Polar or Nonpolar (Determining Solubility)
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on:
October 16, 2008, 04:36:15 PM »
Determine which of the following molecules will dissolve in water:
NaCl
CH3CH2CH2CH2CH2CH2CH2CH2CH2CH2CH3
HOCH2CH2CH2CH2CH2OH
(Where, of course, the numbers above are subscripts).
Thanks for the help. Also, can you tell me how you come to the conclusions you do? That is, how you know which will dissolve in water?
Thanks!
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macman104
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Re: Polar or Nonpolar (Determining Solubility)
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Reply #1 on:
October 16, 2008, 04:52:27 PM »
Is water a polar or nonpolar compound?
Do you know what an ionic compound is?
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DiscreteW
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Re: Polar or Nonpolar (Determining Solubility)
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Reply #2 on:
October 16, 2008, 06:10:44 PM »
Because of water's bent shape, it is a polar molecule.
Yes, I know what an ionic compound is. The ions are held together by ionic bonds (and we know an ion is an atom that has lost/gained an electron- that is, a valence one).
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DiscreteW
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Re: Polar or Nonpolar (Determining Solubility)
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Reply #3 on:
October 16, 2008, 06:16:34 PM »
Hmm, okay, well according to Wikipedia, ionic compounds dissolve in polar solvents, and hence would dissolve in water. So, NaCl would dissolve in water. I guess this is just a given fact that you memorize? What about the others?
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azmanam
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Re: Polar or Nonpolar (Determining Solubility)
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Reply #4 on:
October 16, 2008, 06:26:53 PM »
a good rule of thumb:
like dissolves like
polar compounds typically dissolve in polar solvents. non polar compounds typically do not dissolve in polar solvents.
of the remaining two compounds, are any of them polar?
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DiscreteW
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Re: Polar or Nonpolar (Determining Solubility)
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Reply #5 on:
October 16, 2008, 06:33:15 PM »
Um, well CH3CH2CH2CH2CH2CH2CH2CH2CH2CH2CH3 has the carbon and hydrogen bonds at the end, so I am assuming not since we know all carbon molecules are nonpolar.
HOCH2CH2CH2CH2CH2OH has the alcohol group at the end... I think this is polar?
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macman104
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Re: Polar or Nonpolar (Determining Solubility)
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Reply #6 on:
October 16, 2008, 11:02:39 PM »
Remember that as the carbon length increases the polarity of the molecule decreases because C-H bonds are not polar.
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nj_bartel
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Re: Polar or Nonpolar (Determining Solubility)
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Reply #7 on:
October 17, 2008, 01:51:24 AM »
1,5-pentanediol is pretty in between... it is miscible in water.
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