Yes, I think that website does a good job. Myself, I like to see one more step in the explanation.
There is a three part secret to all of these equilibrium problems. It applies to all equilibrium problems, not just acid-base reactions. Follow it and you will have success.
1) Don't get anxious about the problem.
2) Think out, then write out, all of the balanced reaction equations associated with the problem.
3) Write the equilibrium expressions for the reactions. (product of the conc of the products raised to the power of their coefficients divided by the product of the conc of the reactants raised to the power of their coefficients)
Again, for the hydrolysis reaction, we have:
OAc- + HOH == HOAc + OH-
The equilibrium expression:
[HOAc][OH]
[OAc][HOH]
The trick here is we will multiply by 1: [H]/[H]=1 and get:
[HOAc][OH][H]
[H][OAc][HOH]
=1/Ka*Kw