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Topic: Stoichiometry  (Read 9316 times)

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Offline positiveion

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Stoichiometry
« on: September 20, 2009, 12:31:46 PM »
2-hydroxybenzoic acid + Ethanoic acid --> Aspirin + Water

2C7H6O3 + C4H6O3 --> 2C9H8O4 + H2O

15. g of 2-hydroxybenzoic acid and 15.0 g of ethanoic acid given.

Calculate the mass of aspirin that could be obtained in this reaction.

My working:

2C7H6O3
given: 15.0g
1 mole: 276.26g

C4H6O3
given: 15.06
1 mole: 102.1g

2C7H6O3 is the limiting reagent, so I do the ratio calculations with it.

552.52 : 360.34 = 15 : x
(2 moles of 2-hydroxybenzoic acid to 2 moles of aspirin equates to the given 15 g of 2-hydroxybenzoic acid to the unknown aspirin mass)

552.52/360.34 = 15/x
x(552.52)=15(360.34)
x = 5405.1/552.52
x = 9.782632303

But thats wrong because the answer is 19.6
..

Could you tell me where I went wrong?

Offline Tin Man

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Re: Stoichiometry
« Reply #1 on: September 20, 2009, 01:25:46 PM »
2C7H6O3 + C4H6O3 --> 2C9H8O4 + H2O

2C7H6O3
given: 15.0g
1 mole: 276.26g

I haven't fully checked your work, but I'd look at this here.

The "2" in front of the molecule is a coefficent, representing the mole ratio of this molecule to the rest of the equation. Like I said, I didn't run through your whole equation and check your numbers, but if I were to guess a point where you may have messed up, it would probably be here. You're saying that you have ONE mole of TWO moles of the substance, which is going to make things complicated for you.

One mole of C7H6O3 is 138.06g, half of your answer. Two moles is 276.26g. For every two moles of C7H6O3, you have one mole of C4H6O3, two moles of C9H8O4, and one mole of H2O.

Does that help?
The post below this one is a lie.

Offline positiveion

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Re: Stoichiometry
« Reply #2 on: September 20, 2009, 01:41:26 PM »
Yes thank you so much!

Offline positiveion

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Re: Stoichiometry
« Reply #3 on: September 20, 2009, 01:48:02 PM »
But I am also unsure about how to do the follow up question which is:

if the mass obtained in this experiment was 13.7g, calculate the percentage yield of aspirin.

I had though it would be the grams of aspirin and water added together,

so 2C9H8O4 = 360.32 grams and H20 = 18.02 grams

360.34 + 18.02 = 378.36

360.34/378.36 = 0.9523

Therefore 95%

The answer however is 69.9% and I don't know what I did wrong.

Offline DrCMS

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Re: Stoichiometry
« Reply #4 on: September 20, 2009, 04:25:15 PM »
You did not work out the %yield is the problem. 

I have no idea what you think you're working out.

% yield = actual yield/theoretical yield

Offline positiveion

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Re: Stoichiometry
« Reply #5 on: September 20, 2009, 10:55:15 PM »
How do you find the theoretical yield?

Offline Borek

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Re: Stoichiometry
« Reply #6 on: September 21, 2009, 02:48:10 AM »
From stoichiometry.
ChemBuddy chemical calculators - stoichiometry, pH, concentration, buffer preparation, titrations.info

Offline DrCMS

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Re: Stoichiometry
« Reply #7 on: September 21, 2009, 07:43:55 AM »
How do you find the theoretical yield?

What do you think you calcuated it in part 1?

Offline positiveion

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Re: Stoichiometry
« Reply #8 on: September 21, 2009, 10:35:32 PM »
okay how do you find the actual yield, then?

Offline Borek

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Re: Stoichiometry
« Reply #9 on: September 22, 2009, 02:41:47 AM »
With balance.
ChemBuddy chemical calculators - stoichiometry, pH, concentration, buffer preparation, titrations.info

Offline DrCMS

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Re: Stoichiometry
« Reply #10 on: September 22, 2009, 06:18:33 AM »
okay how do you find the actual yield, then?

You are given it in part 2 - the actual yield is 13.7g. 

(rant deleted)
« Last Edit: September 22, 2009, 10:48:09 AM by Borek »

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