[nightowl1]

Calcium Carbonate reacts with hydrochloric acid to produce carbon dioxide gas.  If 35.3 g of calcium carbonate reacts with 100ml of 6.00 M HCL, how many liters of carbon dioxide gas will be produced at 745mmHg and 23.0Celcius.

Can someone please walk me through this.
I haven't done a limiting reagent problem for about 2 months.

Ca(CO₃) + HCL ----->  CaCl₂ + H₂(CO₃)
I'm not sure if I have to put CO₂ at the end of the equation or not.

The answer to the problem is 7.43L

[nj_bartel]

Carbonic acid decomposes to water and carbon dioxide.

First, balance your equation.  Second, figure out the moles of all of your reagents.  Multiply the moles by their coefficient in the equation.  See which one is smallest (limiting).  Make your calculations using that value.

[nightowl1]

So are you saying the equation should look like this?
Ca(CO₃) + HCL -----> H₂O + CO₂

and balanced it will look like:
Ca(CO₃) + 2HCL -----> H₂O + CO₂

[nightowl1]

Okay the limiting reagent is Calcium Carbonate @ 0.353mol (I think)
Now, how am I suppsed to calculate the number of moles of Carbon Dioxide with this?

[nj_bartel]

So are you saying the equation should look like this?
Ca(CO₃) + HCL -----> H₂O + CO₂

and balanced it will look like:
Ca(CO₃) + 2HCL -----> H₂O + CO₂

Yes

[nj_bartel]

Okay the limiting reagent is Calcium Carbonate @ 0.353mol (I think)
Now, how am I suppsed to calculate the number of moles of Carbon Dioxide with this?

I didn't check your calculations, but if you want to show me how you set up to get that I'll check that.

Anyway, let's assume it's correct.  So you have 0.353 mol calcium carbonate.  How many moles of CO2 are produced per mole of calcium carbonate that reacts?

[nightowl1]

1 mole.
so mole to mole ratio is one to one.
How do i find moles of CO2?

Wait, so does that mean that moles of Carbon Dioxide is the same as moles of Calcium Carbonate? 0.353

[csrscience.com]

Wait, so does that mean that moles of Carbon Dioxide is the same as moles of Calcium Carbonate? 0.353

Yes it does.. its all about ratios 

[nj_bartel]

Yes

Oh, and I think it was accidental, but you left out calcium chloride as a product when you balanced your equations.