[nightowl1]

Hello,
Can someone help me get started on this problem?
Where it states 'Change of' there is a triangle symbol there.

How much engery is released or absorbed when 40.0g of steam at 250C is converted to water at 30C?
specific heat of water = 4.18J/gC           'Change of' H_fus of water is 333 J/g
specific heat of steam = 2.03J/gC           'Change of' H_vap of water is 2260 J/g

[pear]

Q = mcΔT          Q = heat added  (if this is -, then it is heat released)     m = mass       c = specific heat     T = temperature
Q = mΔH_f/v   (<-ΔH_f/v found in tables)



The steam needs to condense, which occurs at 100C-
   1.  Q = (40.0g)(2.031J/gC)(250C-100C)
The phase change is occurs-
   2. Q = (40.0g)(79.72 cal/g)
The water cools from 100C to 30C
  3. Q = (40.0g)(4.18J/gC)(100C-30C)

Adding those Q's should give you the answer.  If you have trouble getting those steps, try drawing out the phase-change graph; for each "line" from your begin to end, you should have a step.  (i.e. only calculating an increase in water temp from 20C to 3OC would only have one; melting ice at -1C to water at 0C would be 2, one for temp change and one for state change)