June 15, 2024, 06:19:46 PM
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Topic: Manganate question!!!  (Read 3008 times)

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Offline Darren

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Manganate question!!!
« on: June 19, 2012, 05:04:21 AM »
For the half equation of MnO4- to form MnO2 in alkaline condition, why does the half equation contain hydrogen ions instead, when its supposed to be alkaline condition?

Offline Hunter2

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Re: Manganate question!!!
« Reply #1 on: June 19, 2012, 05:07:38 AM »
Which equation?  It should contain OH- Ions

Offline Darren

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Re: Manganate question!!!
« Reply #2 on: June 19, 2012, 05:12:34 AM »
MnO4- + 4H+ + 3e-  ::equil:: MnO2 + 2H2O

Offline Hunter2

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Re: Manganate question!!!
« Reply #3 on: June 19, 2012, 05:14:09 AM »
In alkaline this equation is:

MnO4- + 2 H2O + 3 e- => MnO2 + 4 OH-

Offline Darren

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Re: Manganate question!!!
« Reply #4 on: June 19, 2012, 05:16:07 AM »
From the data booklet, thats the equation i got for alkaline condition.why didnt they put the equation you quotes in the first place since its ald in the alkaline condition? If it is in acidic environment, the equation is totally different and Mn2+ is formed instead.

Offline Hunter2

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Re: Manganate question!!!
« Reply #5 on: June 19, 2012, 05:21:34 AM »
I dont know. Maybe write a letter to the writer of the book.

Offline AWK

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Re: Manganate question!!!
« Reply #6 on: June 19, 2012, 06:56:16 AM »
Quote
For the half equation of MnO4- to form MnO2 in alkaline condition
MnO2 is formed in (close to) neutral conditions.
AWK

Offline Hunter2

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Re: Manganate question!!!
« Reply #7 on: June 19, 2012, 07:24:57 AM »
Thats correct. Neutral and alkaline Reaction will be treated in same way as alkaline.


Offline Darren

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Re: Manganate question!!!
« Reply #8 on: June 19, 2012, 07:26:41 AM »
Ok thanks guys for the *delete me* :)

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