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Topic: Oxidation state of iodine  (Read 5528 times)

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Offline Darren

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Oxidation state of iodine
« on: June 19, 2012, 05:30:42 AM »
Whats the oxidation state of iodine in I3-?

Offline Hunter2

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Re: Oxidation state of iodine
« Reply #1 on: June 19, 2012, 06:10:13 AM »
One Iodine is -1 the other two  0. Same rule like in carbonhydrids. C-C is also 0.

For mathematics  in redox reaction how much is the value then for Iodine?
« Last Edit: June 19, 2012, 06:21:30 AM by Hunter2 »

Offline Borek

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Re: Oxidation state of iodine
« Reply #2 on: June 19, 2012, 06:11:57 AM »
You should show your attempts at solving the question to receive help. This is a forum policy.

There is no real physical property that can be measured and that reflects oxidation state of atom. It is nothing unusual to get some strange values.
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Offline Darren

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Re: Oxidation state of iodine
« Reply #3 on: June 19, 2012, 06:22:10 AM »
You should show your attempts at solving the question to receive help. This is a forum policy.

There is no real physical property that can be measured and that reflects oxidation state of atom. It is nothing unusual to get some strange values.

Sorry for not showing my attempt. The qns i ask here are either attepted and still cant be solved by myself or i have no idea at all, otherwise i wouldnt post qns which i havent thought about it for a very long time ald.

Offline Darren

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Re: Oxidation state of iodine
« Reply #4 on: June 19, 2012, 06:23:25 AM »
One Iodine is -1 the other two  0. Same rule like in carbonhydrids. C-C is also 0.

For mathematics  in redox reaction how much is the value then for Iodine?

Could you explain more about carbohydrids? What are they are why can specific oxidation states be given to certain atoms instead of dividing the charge by the total number of atoms?

Offline Hunter2

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Re: Oxidation state of iodine
« Reply #5 on: June 19, 2012, 06:31:01 AM »
Lets have CH4 then Carbon is -4 and the hydrogen each +1.

CH3-CH3 by law a C-C bond is 0, so each Carbon is -3

CH3-CH2-CH3  -3,-2,-3, etc.

or
CH3-COOH  -3, +3 and more examples.

Offline Darren

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Re: Oxidation state of iodine
« Reply #6 on: June 19, 2012, 06:44:22 AM »
Lets have CH4 then Carbon is -4 and the hydrogen each +1.

CH3-CH3 by law a C-C bond is 0, so each Carbon is -3

CH3-CH2-CH3  -3,-2,-3, etc.

or
CH3-COOH  -3, +3 and more examples.

Thank you :)

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Offline Darren

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Re: Oxidation state of iodine
« Reply #8 on: June 19, 2012, 07:27:05 AM »

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