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Topic: Stoichiometry and Reactions  (Read 1749 times)

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Offline GoGoGadget

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Stoichiometry and Reactions
« on: March 05, 2014, 12:23:51 AM »
1. Ten moles of N2O4(l) are added to an unspecified amount N23(CH3)(l) according to the equation shown below:

5 N2O4(l) + 4 N2H3(CH3(l)  :rarrow: 12 H2O(g) + N2 + CO2(g)

If 23 moles of water are produced and the reaction runs to completion, what is the limiting reagent?

A) N2S4(l)

B) N2H3(CH3)(l)

C) H2O(g)

D) There is no limiting reagent.

I ended up getting an answer of C for this one, thinking that we could use the number of moles of H2O and moles of N2O4 from the reaction to determine the amount of total N2H3 produced. However, in reviewing the answering for it, the rationale was that the correct answer was B since we weren't provided with a specified amount and that the reaction would have produced a total of 24 mol of H20 with N2O but how can we assume this to be the case if we're not given a starting amount of N2H3?   ???


2. The following reaction is run to completion:

As4O6(s) + 6C(s)  :rarrow: As4(g) + 6CO(g)

How much carbon is required to produce 75 g of arsenic acid?

A) 12 g

B) 18 g

C) 48 g

D) 72 g

This is how I went about trying to solve it:

75 g As x (1 mol As/300 g As) x (6 mol C/1 mol As) x (12 g C/1 mol C).

I'm not sure if this is the correct approach or not?

Any help is appreciated!

Offline Borek

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Re: Stoichiometry and Reactions
« Reply #1 on: March 05, 2014, 03:14:02 AM »
I ended up getting an answer of C for this one

C points to water which is a PRODUCT - so it can't be a limiting REAGENT.

Quote
However, in reviewing the answering for it, the rationale was that the correct answer was B since we weren't provided with a specified amount and that the reaction would have produced a total of 24 mol of H20 with N2O but how can we assume this to be the case if we're not given a starting amount of N2H3?

How many moles of water would be produced if all 10 moles of N2O4 reacted? Did you got that much? If not - why?

Quote
How much carbon is required to produce 75 g of arsenic acid?

I don't see arsenic acid here.

Quote
75 g As x (1 mol As/300 g As) x (6 mol C/1 mol As) x (12 g C/1 mol C)

This will accidentally produce a correct number (assuming question was about arsenic, not arsenic acid), but if the reaction equation uses As4, you should also use As4 everywhere in your calculations.
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