The thing is; this is a protocol which I'm going to use.
But first, I want to understand the logic behind that.
Of course, some of the compound is in gaseuos phase and some in the liquid phase, I know that. And I used this equilibrium but couldn't find the same answer as they put in the journal reference.
mol(total) = mol(air) + mol(water)
mol(total) = CaVa + CwVw = (KAW)CwVa + CwVw = Cw(KAWVa + Vw)
a:air
w:water
at 25C
KAW:0.27 (Henry's law, dimensionless)
In a 15 ml sealed vial, if all toluene was in the 2 ml solution, it would be 250uM toluene as total. But because of its volatility, only 91 uM is in the 2 ml liquid. I know volatility of toluene is the reason; but I want to calculate this. If the equilibrium on top is wrong, would you mind to write me the exact equation which I can get this result?
Thanks in advance.