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Topic: a (possible) challenge  (Read 15221 times)

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Offline plu

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a (possible) challenge
« on: June 05, 2006, 06:36:00 PM »
A heads-up: This is not a homework problem of mine to which I want the answer.  Just some chemistry fun  ;)

A radioactive gas A is known to react with copper(II) oxide at 500oC.  One of the products of this reaction, B, at the same temperature, reacts with compound M (which contains 75% by mass of Al) to yield a gas C with molar mass equal to 24, and a compound containing 53% by mass Al.  Radioactive decay of one of the atoms of compound C leads to its decomposition giving some charged particles D with molar mass equal to 21, and helium atoms 3He.  Contact of gas C with water vapors gives the molecules of an alcohol E with molar mass of 38, and hydronium ions.

What compounds are represented by letters A, B, C, D, E, and M.

Offline Borek

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Re: a (possible) challenge
« Reply #1 on: June 05, 2006, 07:02:50 PM »
Nice one :)

Pó?okres 12.32 roku :P
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Offline technologist

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Re: a (possible) challenge
« Reply #2 on: June 06, 2006, 12:04:42 AM »
Your problems is erratic. Here it is -

Quote
to yield a gas C with molar mass equal to 24

And then

Quote
Contact of gas C with water vapors gives the molecules of an alcohol E with molar mass of 38, and hydronium ions

These 2 statements contradict molar mass of C which is mentioned as 24 in first Quote & 39 based on II Quote.

Edited to not spoil fun for others :)

Since, Challenge (possible) is deciphered, remaining things are to be solved by you & its a matter of time only, which I cant devote right now.

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« Last Edit: June 06, 2006, 03:10:02 AM by Borek »

Offline Borek

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Re: a (possible) challenge
« Reply #3 on: June 06, 2006, 03:11:25 AM »
Your problems is erratic. Here it is -

Quote
to yield a gas C with molar mass equal to 24

And then

Quote
Contact of gas C with water vapors gives the molecules of an alcohol E with molar mass of 38, and hydronium ions

These 2 statements contradict molar mass of C which is mentioned as 24 in first Quote & 39 based on II Quote.

No, you got confused by the second statement.
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Offline plu

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Re: a (possible) challenge
« Reply #4 on: June 06, 2006, 08:48:15 AM »
Pó?okres 12.32 roku :P

What does this mean, Borek?

Offline Borek

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Re: a (possible) challenge
« Reply #5 on: June 06, 2006, 09:00:32 AM »
It is a proof I know the answer, but I didn't want to spoil fun for others :)
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wildstar

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Re: a (possible) challenge
« Reply #6 on: June 19, 2006, 01:26:22 PM »
A: T2
B: T2O
C: CT4
D: CT3+
E: CT3OH
M: Al4C3

Offline technologist

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Re: a (possible) challenge
« Reply #7 on: June 20, 2006, 12:14:39 AM »
I am completely knocked to know that we were talking about hypothetical compounds. I also learned from the reply of wildstar that T=3 (I dont know whether this answer is correct or not, Borek can tell us). Anyone know a gas T2 type with MW=6. I know only Li=3.

Further, as I wrote in my doubt, C =24 with water gives E = 38 + Hydronium Ions = 19 which is not balancing.

Real chemistry problems or FUN is different than based on hypo compounds & nos.

Offline AWK

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Re: a (possible) challenge
« Reply #8 on: June 20, 2006, 01:26:27 AM »

Further, as I wrote in my doubt, C =24 with water gives E = 38 + Hydronium Ions = 19 which is not balancing.

CT4 + H2O = CT3OH + HT
It is balanced, but I agree the reaction is slightly strained
AWK

Offline Borek

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Re: a (possible) challenge
« Reply #9 on: June 20, 2006, 04:08:10 AM »
I am completely knocked to know that we were talking about hypothetical compounds.

None of these compounds is hypothetical! T stands for Tritium, isotope of hydrogen. You were told that substance is radioactive.

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Offline technologist

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Re: a (possible) challenge
« Reply #10 on: June 20, 2006, 05:21:47 AM »
Quote
CT4 + H2O = CT3OH + HT
I thought Hydronium Ion is H3O+.

So

CT4 + H2O = CT3OH + H3O+, Which is not obviously fit.

Also, if I replace T (Tritium as suggested by Borek) with H in your equation (Just to show the possibility of reaction) it should give me

CH4 + H2O = CH3OH + 2H2, which doesnt happen.

Offline Borek

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Re: a (possible) challenge
« Reply #11 on: June 20, 2006, 05:42:21 AM »
Quote
Contact of gas C with water vapors gives the molecules of an alcohol E with molar mass of 38, and hydronium ions.

Everything is OK here. When tritium decays:

CT4 -> CT3+ + 3He + e-

Then:

CT3+ + 2H2O -> CT3OH + H3O+

See how molar masses agree with the question - CT4 is 24, CT3OH is 38.

It was never stated that this reaction needs one water particle, nor that it is CT4 that reacts with water - that was only your interpretation. You have made several hidden assumptions, that stopped you from seeing the answer :)



Edit: corrected stupid mistake signalled by AWK.
« Last Edit: June 20, 2006, 06:23:31 AM by Borek »
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Offline AWK

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Re: a (possible) challenge
« Reply #12 on: June 20, 2006, 06:15:58 AM »
Quote
- CT3+ is 24,
CT3+ is 21
AWK

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