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Topic: 3 fold symmetry  (Read 5110 times)

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Offline Morphic flip

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3 fold symmetry
« on: June 17, 2006, 07:36:47 AM »
How would a benzene ring be attached to Rh3(CO)9 to create a 3 fold axis of symmetry?
I make each Rh bonding to three (CO)3 groups have 16 electrons, so the remaining 2 electrons needed must be the attachment of another Rhodium to form a triangular arrangement and the benzene ring.
I can only see it as one bond per Rhodium to the benzene ring, but then the bonding in benzene ring would be uneven
Rhodium is 3d8
« Last Edit: June 18, 2006, 07:33:08 AM by Morphic flip »

Offline Dan

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Re: 3 fold symmetry
« Reply #1 on: July 08, 2006, 03:47:00 PM »
maybe each Rh co-ordinates to benzene in a n2 fashion - as it would to an isolated C=C bond. I'd bet a large amount of money that its fluxional too...
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