Ahh... I actually got this assigned to me today too... Can someone help me?

THis is what i did so far:

i made two half reactions:

MnO4- ---> MnS and S2- ---> S

Then i balanced the charges and elements on both and i got:

4H+ + S + MnO4- + 3e- ---> MnS + 4H2O

and

S2- ---> S + 2 e-

then i balanced the electrons on both the equations so they would cancel out:

2(4H+ + S + MnO4- + 3e- ---> MnS + 4H2O)

and

3(S2- ---> S + 2 e-)

THEN I put the equations together and got:

8H+ + S + 2MnO4- + 3S2- ---> 2MnS + 8H2O + 3S

I'm not sure if i did that last step right...

but after that since there's 8H on the right I added 8OH- to both sides... is that correct?

so the final equation i got was

8OH- + 8H+ + S + 2MnO4- + 3S2- ---> 2MnS + 8H2O + 3S + 8OH-

Did I do any of this right!?

If I'm doing anything wrong... What is it?

Pleeease help